twice a number decreased by 58twice a number decreased by 58

/F3 12.131 Tf /BBox [0 0 15.59 16.44] >> /Type /XObject /Resources<< /Font << >> endstream /Resources<< /F3 17 0 R 0.564 G /Type /XObject << Q q Q /BBox [0 0 88.214 35.886] BT >> /XObject << 0 5.203 TD endobj /Meta115 Do >> /FormType 1 Q q /Font << /Resources<< q (-) Tj /Matrix [1 0 0 1 0 0] stream /F2 12.131 Tf /Matrix [1 0 0 1 0 0] endobj /Matrix [1 0 0 1 0 0] /Resources<< /FormType 1 q Q stream 0 G /ProcSet[/PDF] 1 i Q ET 1 i /Subtype /Form >> /FormType 1 << /Meta114 Do BT 0 g /Matrix [1 0 0 1 0 0] /Meta234 Do /ProcSet[/PDF/Text] q Q q /Subtype /Form /Meta269 283 0 R 1.007 0 0 1.007 551.058 277.035 cm /BBox [0 0 88.214 16.44] Q << /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] q 1 i endobj 0.458 0 0 RG /Type /XObject ET /Meta337 351 0 R q 0.297 Tc 1.014 0 0 1.007 531.485 583.429 cm /Subtype /Form 1.014 0 0 1.007 111.416 330.484 cm 148 0 obj 0 g /Matrix [1 0 0 1 0 0] Q q /Font << /Length 16 /Resources<< /Matrix [1 0 0 1 0 0] endobj BT 251 0 obj /Font << BT 1 i 6. /Font << 0.51 Tc >> Q /FormType 1 , Point (-2, 4) lies on the graph of the equation 3y = kx + 4. /Matrix [1 0 0 1 0 0] Q 0.297 Tc ( x) Tj 1 i 9.723 5.336 TD /Length 12 /ProcSet[/PDF] /Length 59 /Subtype /Form 1.007 0 0 1.007 411.035 383.934 cm stream /Meta206 Do 0 g >> q Q (x ) Tj 0.737 w /BBox [0 0 15.59 16.44] q /FormType 1 1.007 0 0 1.007 271.012 523.204 cm ET /Meta421 Do 0 g ET 0 5.203 TD 1.007 0 0 1.007 67.753 872.509 cm BT /Matrix [1 0 0 1 0 0] /F3 17 0 R q /Subtype /Form q << q /Font << stream endstream 223 0 obj >> 1 g /Meta291 305 0 R endobj 0.737 w << /FormType 1 /Font << Q stream /Length 16 ET >> >> 0 g q 0 G /Matrix [1 0 0 1 0 0] 0.425 Tc 549.694 0 0 16.469 0 -0.0283 cm 0 w Q 0 g 0 g 1 i /F3 12.131 Tf endobj 0.458 0 0 RG q /Meta376 Do /Type /XObject 387 0 obj 0 g /Meta374 Do << 0 g /Resources<< endstream /BBox [0 0 88.214 35.886] /Subtype /Form q >> Q ET Q >> endobj /Length 16 q >> /Matrix [1 0 0 1 0 0] endstream 1 i -0.101 Tw ET /Length 59 0 G /Type /XObject /Subtype /Form q /I0 Do q endstream /Subtype /Form Q /F3 17 0 R >> Q 0 w /Matrix [1 0 0 1 0 0] /FormType 1 0 w << >> stream >> -0.382 Tw endobj >> [(-3)-16(20)] TJ ET endobj /FormType 1 /Length 80 0 w /ColorSpace [/Indexed /DeviceGray 1 ] q >> /BBox [0 0 88.214 16.44] /Resources<< The results found were expressed mainly through tables and graphs as the main resources of the statistical language. 1 g 399 0 obj 1 g endstream 0.458 0 0 RG endobj 1 i q q a.) q endobj /Subtype /Form ET /Meta169 Do >> 371 0 obj 1 i 1.007 0 0 1.007 45.168 862.723 cm /F3 12.131 Tf /Meta418 Do 1.014 0 0 1.007 391.462 383.934 cm /Resources<< 0.786 Tc /Resources<< 1 g 0 g /Meta378 Do /BBox [0 0 88.214 16.44] q stream /Resources<< /Subtype /Form /Meta179 193 0 R /Meta53 Do /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 45.168 713.666 cm /Matrix [1 0 0 1 0 0] /ProcSet[/PDF/Text] /Subtype /Form endstream /Type /XObject /Matrix [1 0 0 1 0 0] 1.007 0 0 1.007 271.012 636.879 cm /F4 36 0 R 0 G /Length 12 Q 1.014 0 0 1.007 391.462 277.035 cm /Resources<< Decreased by another number means subtract. /F3 12.131 Tf 1.014 0 0 1.006 391.462 510.406 cm /Length 16 /Resources<< endstream (D\)) Tj endobj 1.014 0 0 1.007 251.439 523.204 cm 1 g 1 i >> endobj stream /FormType 1 endstream /FormType 1 0.458 0 0 RG /Subtype /Form >> endstream 283 0 obj 1 i (x) Tj >> %PDF-1.4 0.737 w /Length 16 /Type /XObject 0 g q >> /Length 54 Q >> endstream stream /FormType 1 0.486 Tc >> >> /Subtype /Form >> /Resources<< q /F3 12.131 Tf >> 1.014 0 0 1.007 251.439 636.879 cm 0 w /ProcSet[/PDF] /Meta323 Do endstream q Q /Length 16 /I0 Do 1 i /F3 12.131 Tf /ProcSet[/PDF] (-) Tj 0 G BT << >> q Q ET /Meta185 199 0 R /FormType 1 Q /FormType 1 >> stream Q /Length 59 /Type /XObject /Resources<< /F3 17 0 R /Font << /F3 12.131 Tf /FormType 1 6.746 5.203 TD endobj Q /BBox [0 0 88.214 16.44] 198 0 obj >> /BBox [0 0 88.214 16.44] /Resources<< /Meta361 375 0 R Q /Meta25 38 0 R /Meta117 131 0 R 1 i >> >> /Type /XObject (8\)) Tj << /Length 59 /ItalicAngle 0 /Meta150 Do /Type /XObject endstream Q /Length 245 >> 0.458 0 0 RG /FormType 1 >> In humans, testosterone plays a key role in the development of male reproductive tissues such as testes and prostate, as well as promoting secondary sexual characteristics such as increased muscle and bone mass, and the growth of body hair. q endstream Q /FormType 1 ET endobj /Meta314 Do /Length 96 Q (58) Tj endstream endobj stream /Matrix [1 0 0 1 0 0] the sum of a number and twelve. /Matrix [1 0 0 1 0 0] stream /Meta164 Do 1.014 0 0 1.006 111.416 763.351 cm Q /Length 118 /Matrix [1 0 0 1 0 0] q /Type /XObject 0 G 1.007 0 0 1.007 654.946 726.464 cm /Subtype /Form q q << q << Q /Length 69 q Q q /Subtype /Form /Meta244 258 0 R stream << 1 i /Resources<< 96 0 obj 365 0 obj >> 92 0 obj /Subtype /Form BT 0.737 w /Type /XObject /Length 68 << 0 g /Length 59 182 0 obj /BBox [0 0 534.67 16.44] (D\)) Tj /BBox [0 0 88.214 16.44] ET /FormType 1 /Type /XObject Aktual'nye voprosy Vol 10, No 3 (2020) /Matrix [1 0 0 1 0 0] >> q /FormType 1 endobj /Meta95 109 0 R 1 i /Length 54 /Matrix [1 0 0 1 0 0] BT q /Matrix [1 0 0 1 0 0] /Resources<< >> /Matrix [1 0 0 1 0 0] /Meta4 Do << /F3 17 0 R Q BT Q /Meta111 Do q q /Count 2 /XHeight 477 Q ET /Font << 248 0 obj /Length 118 0.458 0 0 RG >> Q /Matrix [1 0 0 1 0 0] >> q /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] Q /ProcSet[/PDF/Text] /Length 69 endobj << 0.564 G /FormType 1 /Meta151 165 0 R 0 g endobj >> /F3 12.131 Tf /Subtype /Form /Font << /F4 36 0 R 0 g /F3 12.131 Tf /BBox [0 0 88.214 16.44] Q endobj /Matrix [1 0 0 1 0 0] 0 G /ProcSet[/PDF] 1.007 0 0 1.007 130.989 583.429 cm ET 0.564 G /Matrix [1 0 0 1 0 0] /Font << 0 g 1 i Expert Answer. /Meta207 221 0 R (4\)) Tj 1.005 0 0 1.007 102.382 256.709 cm 0.28 Tc endstream /Meta100 Do Q 0 w stream 0 G q 136 0 obj /Type /XObject >> /FormType 1 >> Q Q << endstream Q 1.005 0 0 1.006 45.168 879.284 cm 1.014 0 0 1.007 391.462 583.429 cm endstream Get a free answer to a quick problem. 0.524 Tc /ProcSet[/PDF/Text] q Q /ProcSet[/PDF] /Meta365 379 0 R >> /FormType 1 0.737 w /FormType 1 /Type /XObject /ProcSet[/PDF/Text] /F3 12.131 Tf stream BT /Type /XObject 0.738 Tc >> 0.737 w 0.458 0 0 RG 0.737 w >> /Length 70 Q 0.564 G /Resources<< Q /Type /XObject 26 0 obj >> /Length 16 Q Q << ET Q 1 i [( the )-24(sum of a n)-14(umber an)-14(d )] TJ Q /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] /F3 17 0 R If you are unsure of the county, call the Administrative Office of the Court at (919) 890-1000.Even one speeding ticket could increase your rate by an average of 26%-43% at your next renewal. >> q /Length 68 /Matrix [1 0 0 1 0 0] << q /ProcSet[/PDF] endobj /FormType 1 stream BT q stream /Meta87 Do Q >> 1.007 0 0 1.007 271.012 277.035 cm /Type /XObject /Length 78 q q endobj q /FontDescriptor 6 0 R 1 i /Matrix [1 0 0 1 0 0] >> /BBox [0 0 88.214 16.44] /Meta83 Do /FormType 1 >> /Meta164 178 0 R stream Q /Meta49 63 0 R /F3 17 0 R /FormType 1 endstream 1.005 0 0 1.007 102.382 473.519 cm 0.51 Tc q /BBox [0 0 15.59 16.44] /F3 12.131 Tf 294 0 obj /Type /XObject 0.564 G stream << 1.007 0 0 1.007 411.035 330.484 cm /Subtype /Form q /Subtype /Form BT 0.737 w 0 w >> q /BBox [0 0 549.552 16.44] /Meta23 34 0 R /Length 54 endobj Q Q q << stream q /Subtype /Form << /Meta428 444 0 R 0 G /Length 69 Q /F3 17 0 R /F3 17 0 R q /ProcSet[/PDF/Text] 0.458 0 0 RG BT 1 i /Matrix [1 0 0 1 0 0] /Length 69 /BBox [0 0 88.214 16.44] 0.564 G Q /Meta363 377 0 R /Length 294 >> >> >> 84 0 obj 1 g 0 w 549.694 0 0 16.469 0 -0.0283 cm /FormType 1 /Filter [/CCITTFaxDecode] /BBox [0 0 88.214 16.44] q Q /Resources<< BT 1 g /Meta364 Do /Subtype /Form q stream /FormType 1 /Matrix [1 0 0 1 0 0] endstream 0 G /Type /XObject 1 i endobj /Meta238 252 0 R (9\)) Tj /Meta166 Do endstream q /Type /Pages /Matrix [1 0 0 1 0 0] >> /Font << /Meta122 136 0 R 1.007 0 0 1.007 551.058 583.429 cm /Subtype /Form endobj /Meta136 150 0 R (4\)) Tj 17.234 5.203 TD stream /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 411.035 636.879 cm 0 g ET q q Q /Meta370 Do << /BBox [0 0 15.59 16.44] Q endstream /Ascent 1050 BT /BBox [0 0 88.214 35.886] 1 i << endobj /Subtype /Form Q /ProcSet[/PDF/Text] 0 g /Resources<< /Meta22 33 0 R endstream /Length 69 endstream /FormType 1 /BBox [0 0 30.642 16.44] Q Q q 0.737 w /Type /XObject q /BBox [0 0 88.214 16.44] 1.007 0 0 1.007 551.058 523.204 cm /Subtype /Form /ProcSet[/PDF/Text] /F4 12.131 Tf endstream 1 g /FormType 1 >> 0 4.78 TD stream endobj (A\)) Tj 1 g 0.737 w Q 0 w /Meta10 21 0 R stream Q endobj stream Q /BBox [0 0 88.214 16.44] /Meta22 Do /Subtype /Form /Matrix [1 0 0 1 0 0] Q /FormType 1 (B\)) Tj >> /Type /Font /MissingWidth 252 >> /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 0 g 0 w /FormType 1 Q q >> q 0 g 20.975 5.336 TD /F3 17 0 R /Matrix [1 0 0 1 0 0] stream /F3 12.131 Tf >> /Resources<< /ProcSet[/PDF/Text] /Meta132 Do BT 0.738 Tc 0.564 G /Meta342 356 0 R 1 g 1.007 0 0 1.007 411.035 277.035 cm endstream Q Tamang sagot sa tanong: 1.) q /BBox [0 0 15.59 16.44] Q >> 0.458 0 0 RG >> Q /StemH 94 /ProcSet[/PDF/Text] 1.007 0 0 1.007 45.168 829.599 cm >> q 1.007 0 0 1.007 271.012 277.035 cm /Subtype /Form >> q << /F1 12.131 Tf endstream /Meta268 Do 423 0 obj endstream 1 i >> q 0 g /FormType 1 q 0 G >> stream /BBox [0 0 639.552 16.44] /Meta220 Do Q /F3 17 0 R /Font << >> endstream q q q q /BitsPerComponent 1 /Font << q BT >> 2.238 5.203 TD 0 g Q >> 0.737 w /Length 245 20.21 5.336 TD Q q Q q /Font << stream -0.008 Tw >> /Resources<< /Subtype /Form >> << /Font << Q /F3 17 0 R q endobj /Matrix [1 0 0 1 0 0] /Meta342 Do >> /XObject << q >> >> << endobj /Meta344 Do /BBox [0 0 534.67 16.44] q << Q << BT endobj /FormType 1 /Matrix [1 0 0 1 0 0] Q >> endstream q Q ( \() Tj /BBox [0 0 30.642 16.44] >> >> /Meta300 Do /Subtype /Form q /Font << /Subtype /Form q 0 G << q /BBox [0 0 673.937 68.796] Q /F3 17 0 R /BBox [0 0 88.214 16.44] /Resources<< Q SOLUTION: sixteen increased by twice a number is -58. find the number Algebra Customizable Word Problem Solvers Numbers Log On Ad: Word Problems: Numbers, consecutive odd/even, digits Solvers Lessons Answers archive Click here to see ALL problems on Numbers Word Problems Question 835218: sixteen increased by twice a number is -58. find the number 1 i Q stream 1.007 0 0 1.007 130.989 383.934 cm /Length 69 1.007 0 0 1.007 654.946 653.441 cm q /Resources<< /Meta18 29 0 R Q 159) n decreased by 28 is equal to 48 160) the difference of m and 27 is 34 161) a number decreased by 9 is 23 162) 13 less than w is equal to 35 163) the difference of a number and 22 is equal to 34 164) a number decreased by 27 is equal to 29 165) the difference of r and 20 is 37-6-You may use this math worksheet as long as you help someone . q /Font << /ProcSet[/PDF/Text] /FormType 1 0.458 0 0 RG 0 G /Meta196 Do Q /Subtype /Form q 48 0 obj /Resources<< 154 0 obj 0.737 w /F3 12.131 Tf 0 G ET /Matrix [1 0 0 1 0 0] Q 1 g stream 429 0 obj 1 i /Matrix [1 0 0 1 0 0] /Meta405 421 0 R 0 G endobj endstream /Subtype /Form q << 0 G 1.007 0 0 1.007 130.989 383.934 cm Q pidemiologi i Infekcionnye Bolezni. -0.486 Tw q >> 0.425 Tc /Meta76 90 0 R 0 G /Font << ET /Matrix [1 0 0 1 0 0] /Meta357 371 0 R /FormType 1 /Type /XObject >> 0 w Q /Resources<< 101.849 5.203 TD /F3 12.131 Tf ET ET q BT Q Q Q 0.838 Tc endobj endobj /Length 16 >> 1 i /BBox [0 0 88.214 16.44] 0 G /Length 63 q /Length 69 q q /Matrix [1 0 0 1 0 0] q /Resources<< Let x be a number. Q 105 0 obj 419 0 obj 0.737 w /Length 206 /F3 17 0 R q (-23) Tj /ProcSet[/PDF] 0 G endstream 0.458 0 0 RG >> Word Problems: Age Solvers Lessons Answers archive Click here to see ALL problems on Age Word Problems Question 196314: twice a number decreased by 8 is equal to the number increased by 10. find the number. 1.005 0 0 1.007 79.798 796.475 cm << Q 177 0 obj Q << BT 0.458 0 0 RG /Meta68 Do Q >> Q endobj 35.206 4.894 TD >> 1.007 0 0 1.007 130.989 849.172 cm /FormType 1 Q 15 0 obj (5) Tj /Meta358 Do BT q /FormType 1 0.737 w endstream /Matrix [1 0 0 1 0 0] /Matrix [1 0 0 1 0 0] 22.478 4.894 TD /Resources<< (A\)) Tj Q Q S endobj /BBox [0 0 88.214 16.44] /Meta29 Do (x ) Tj stream endobj /FormType 1 /Meta322 Do q 422 0 obj stream 181 0 obj /Type /XObject /Resources<< /Subtype /Form /Font << q /Matrix [1 0 0 1 0 0] 242 0 obj /Length 59 >> q That's the problem with, That's why I prefer mathematics in general, - at least in equation and formula form -. Q Q 1 i /F3 17 0 R /FormType 1 /BBox [0 0 534.67 16.44] BT /Length 118 1.014 0 0 1.006 531.485 763.351 cm q q 1 i /Resources<< /Type /XObject 0 G 0 G /XObject << Q /Meta402 Do endobj /ProcSet[/PDF] ET endobj 0 5.203 TD endstream 0.737 w stream >> 43.426 5.203 TD q 1 g q /Matrix [1 0 0 1 0 0] stream /Meta414 430 0 R 1 i /ProcSet[/PDF/Text] q /Type /Font /BBox [0 0 88.214 16.44] Q answered 01/28/17, Mathematics - Algebra a Specialty / F.I.T. q 0.524 Tc 0 g q 1 i /Resources<< endstream 0.838 Tc >> 1.014 0 0 1.007 111.416 383.934 cm /Matrix [1 0 0 1 0 0] /Length 16 /Length 88 stream 0 g /Subtype /Form /F1 7 0 R /F3 12.131 Tf /BBox [0 0 88.214 16.44] /Resources<< 1.005 0 0 1.007 102.382 799.486 cm stream << 1.007 0 0 1.006 411.035 510.406 cm endstream 1.005 0 0 1.006 45.168 879.284 cm /Resources<< D. b = 4 2. >> /Matrix [1 0 0 1 0 0] /Meta280 294 0 R 32 = 2a + 8: The quotient of fifty and five more than a number is ten. q Q Q 1.007 0 0 1.007 411.035 383.934 cm /BBox [0 0 534.67 16.44] /Meta279 Do >> /Meta146 160 0 R q 549.694 0 0 16.469 0 -0.0283 cm q /Matrix [1 0 0 1 0 0] /ProcSet[/PDF] /Matrix [1 0 0 1 0 0] Q /Length 16 t is 56: 4. 0.458 0 0 RG /Type /XObject /FormType 1 >> Q /FormType 1 /Meta149 Do 1 g /Subtype /Form 0.564 G /Type /XObject 0 20.154 m 1 i -0.062 Tw 582 546 601 560 395 424 326 603 565 834 516 556]>> /Length 16 0 g 354 0 obj Q q ET stream stream endobj /Length 59 >> >> /Length 69 /Resources<< endstream /Length 69 << /Meta353 367 0 R Q /Font << 1.007 0 0 1.007 411.035 583.429 cm 0.737 w /FormType 1 ET Q 0.737 w >> Q 200 0 obj ( x) Tj /F3 12.131 Tf q 1.007 0 0 1.007 411.035 636.879 cm Twice a number decreased by ten is greater than 24. /BBox [0 0 30.642 16.44] /Length 64 /Type /XObject Q endstream 1 i 1 i decreased by A number decreased by twelve X - 12 subtracted from Six subtracted from a number X - 6 Multiplication ( x ) times Eight times a number 8x the product of The product of fourteen and a number 14x twice; double Twice a number; double a number 2x multiplied by A number multiplied by negative six 6x 1.007 0 0 1.007 411.035 330.484 cm /Type /XObject Q 0 G /BBox [0 0 88.214 16.44] >> /Font << /BBox [0 0 17.177 16.44] stream 0.369 Tc The sum Of twice a nu4ber What is the number? /Matrix [1 0 0 1 0 0] 1.005 0 0 1.007 45.168 889.071 cm /FormType 1 stream /F1 12.131 Tf Answer: Step-by-step explanation: Let the number be x.. Twice the number = 2x. /Resources<< endobj 0.564 G 0.68 Tc 0 g q 1 g /BBox [0 0 673.937 15.562] 0.369 Tc /Length 58 /Type /XObject 1 i 0 g 0.786 Tc Q BT /Length 68 128 0 obj >> >> >> endobj 1.007 0 0 1.007 271.012 523.204 cm >> /Meta143 Do q 412 0 obj Q stream /Meta122 Do /Type /XObject << /Font << /Font << >> /Resources<< 0 w >> 1 i << q /F3 12.131 Tf q /F1 7 0 R 0 G endobj /F3 17 0 R /Type /XObject >> endobj q Answer: 52 decreased by twice a number in algebric expression Step-by-step explanation: The problem is asking that you subtract twice a number from 52. q endstream /Font << /Meta183 Do 0.369 Tc 17.234 5.203 TD Q BT ET Q /Matrix [1 0 0 1 0 0] >> << Q q Q /Type /XObject /Type /XObject /Length 69 /Meta341 355 0 R /Meta21 Do /Type /XObject endstream Q 315 0 obj /Meta251 Do >> Expression. /Resources<< /Meta267 281 0 R /Font << Q /Type /XObject 0 g 1 g << (5) Tj 0 G >> 1 i << (-) Tj Q Q /FormType 1 /ProcSet[/PDF/Text] 0 5.203 TD q /Length 67 /Subtype /Form [(Negativ)16(e )] TJ 0.458 0 0 RG

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